do_csum.S (10298B)
1/* SPDX-License-Identifier: GPL-2.0 */ 2/* 3 * 4 * Optmized version of the standard do_csum() function 5 * 6 * Return: a 64bit quantity containing the 16bit Internet checksum 7 * 8 * Inputs: 9 * in0: address of buffer to checksum (char *) 10 * in1: length of the buffer (int) 11 * 12 * Copyright (C) 1999, 2001-2002 Hewlett-Packard Co 13 * Stephane Eranian <eranian@hpl.hp.com> 14 * 15 * 02/04/22 Ken Chen <kenneth.w.chen@intel.com> 16 * Data locality study on the checksum buffer. 17 * More optimization cleanup - remove excessive stop bits. 18 * 02/04/08 David Mosberger <davidm@hpl.hp.com> 19 * More cleanup and tuning. 20 * 01/04/18 Jun Nakajima <jun.nakajima@intel.com> 21 * Clean up and optimize and the software pipeline, loading two 22 * back-to-back 8-byte words per loop. Clean up the initialization 23 * for the loop. Support the cases where load latency = 1 or 2. 24 * Set CONFIG_IA64_LOAD_LATENCY to 1 or 2 (default). 25 */ 26 27#include <asm/asmmacro.h> 28 29// 30// Theory of operations: 31// The goal is to go as quickly as possible to the point where 32// we can checksum 16 bytes/loop. Before reaching that point we must 33// take care of incorrect alignment of first byte. 34// 35// The code hereafter also takes care of the "tail" part of the buffer 36// before entering the core loop, if any. The checksum is a sum so it 37// allows us to commute operations. So we do the "head" and "tail" 38// first to finish at full speed in the body. Once we get the head and 39// tail values, we feed them into the pipeline, very handy initialization. 40// 41// Of course we deal with the special case where the whole buffer fits 42// into one 8 byte word. In this case we have only one entry in the pipeline. 43// 44// We use a (LOAD_LATENCY+2)-stage pipeline in the loop to account for 45// possible load latency and also to accommodate for head and tail. 46// 47// The end of the function deals with folding the checksum from 64bits 48// down to 16bits taking care of the carry. 49// 50// This version avoids synchronization in the core loop by also using a 51// pipeline for the accumulation of the checksum in resultx[] (x=1,2). 52// 53// wordx[] (x=1,2) 54// |---| 55// | | 0 : new value loaded in pipeline 56// |---| 57// | | - : in transit data 58// |---| 59// | | LOAD_LATENCY : current value to add to checksum 60// |---| 61// | | LOAD_LATENCY+1 : previous value added to checksum 62// |---| (previous iteration) 63// 64// resultx[] (x=1,2) 65// |---| 66// | | 0 : initial value 67// |---| 68// | | LOAD_LATENCY-1 : new checksum 69// |---| 70// | | LOAD_LATENCY : previous value of checksum 71// |---| 72// | | LOAD_LATENCY+1 : final checksum when out of the loop 73// |---| 74// 75// 76// See RFC1071 "Computing the Internet Checksum" for various techniques for 77// calculating the Internet checksum. 78// 79// NOT YET DONE: 80// - Maybe another algorithm which would take care of the folding at the 81// end in a different manner 82// - Work with people more knowledgeable than me on the network stack 83// to figure out if we could not split the function depending on the 84// type of packet or alignment we get. Like the ip_fast_csum() routine 85// where we know we have at least 20bytes worth of data to checksum. 86// - Do a better job of handling small packets. 87// - Note on prefetching: it was found that under various load, i.e. ftp read/write, 88// nfs read/write, the L1 cache hit rate is at 60% and L2 cache hit rate is at 99.8% 89// on the data that buffer points to (partly because the checksum is often preceded by 90// a copy_from_user()). This finding indiate that lfetch will not be beneficial since 91// the data is already in the cache. 92// 93 94#define saved_pfs r11 95#define hmask r16 96#define tmask r17 97#define first1 r18 98#define firstval r19 99#define firstoff r20 100#define last r21 101#define lastval r22 102#define lastoff r23 103#define saved_lc r24 104#define saved_pr r25 105#define tmp1 r26 106#define tmp2 r27 107#define tmp3 r28 108#define carry1 r29 109#define carry2 r30 110#define first2 r31 111 112#define buf in0 113#define len in1 114 115#define LOAD_LATENCY 2 // XXX fix me 116 117#if (LOAD_LATENCY != 1) && (LOAD_LATENCY != 2) 118# error "Only 1 or 2 is supported/tested for LOAD_LATENCY." 119#endif 120 121#define PIPE_DEPTH (LOAD_LATENCY+2) 122#define ELD p[LOAD_LATENCY] // end of load 123#define ELD_1 p[LOAD_LATENCY+1] // and next stage 124 125// unsigned long do_csum(unsigned char *buf,long len) 126 127GLOBAL_ENTRY(do_csum) 128 .prologue 129 .save ar.pfs, saved_pfs 130 alloc saved_pfs=ar.pfs,2,16,0,16 131 .rotr word1[4], word2[4],result1[LOAD_LATENCY+2],result2[LOAD_LATENCY+2] 132 .rotp p[PIPE_DEPTH], pC1[2], pC2[2] 133 mov ret0=r0 // in case we have zero length 134 cmp.lt p0,p6=r0,len // check for zero length or negative (32bit len) 135 ;; 136 add tmp1=buf,len // last byte's address 137 .save pr, saved_pr 138 mov saved_pr=pr // preserve predicates (rotation) 139(p6) br.ret.spnt.many rp // return if zero or negative length 140 141 mov hmask=-1 // initialize head mask 142 tbit.nz p15,p0=buf,0 // is buf an odd address? 143 and first1=-8,buf // 8-byte align down address of first1 element 144 145 and firstoff=7,buf // how many bytes off for first1 element 146 mov tmask=-1 // initialize tail mask 147 148 ;; 149 adds tmp2=-1,tmp1 // last-1 150 and lastoff=7,tmp1 // how many bytes off for last element 151 ;; 152 sub tmp1=8,lastoff // complement to lastoff 153 and last=-8,tmp2 // address of word containing last byte 154 ;; 155 sub tmp3=last,first1 // tmp3=distance from first1 to last 156 .save ar.lc, saved_lc 157 mov saved_lc=ar.lc // save lc 158 cmp.eq p8,p9=last,first1 // everything fits in one word ? 159 160 ld8 firstval=[first1],8 // load, ahead of time, "first1" word 161 and tmp1=7, tmp1 // make sure that if tmp1==8 -> tmp1=0 162 shl tmp2=firstoff,3 // number of bits 163 ;; 164(p9) ld8 lastval=[last] // load, ahead of time, "last" word, if needed 165 shl tmp1=tmp1,3 // number of bits 166(p9) adds tmp3=-8,tmp3 // effectively loaded 167 ;; 168(p8) mov lastval=r0 // we don't need lastval if first1==last 169 shl hmask=hmask,tmp2 // build head mask, mask off [0,first1off[ 170 shr.u tmask=tmask,tmp1 // build tail mask, mask off ]8,lastoff] 171 ;; 172 .body 173#define count tmp3 174 175(p8) and hmask=hmask,tmask // apply tail mask to head mask if 1 word only 176(p9) and word2[0]=lastval,tmask // mask last it as appropriate 177 shr.u count=count,3 // how many 8-byte? 178 ;; 179 // If count is odd, finish this 8-byte word so that we can 180 // load two back-to-back 8-byte words per loop thereafter. 181 and word1[0]=firstval,hmask // and mask it as appropriate 182 tbit.nz p10,p11=count,0 // if (count is odd) 183 ;; 184(p8) mov result1[0]=word1[0] 185(p9) add result1[0]=word1[0],word2[0] 186 ;; 187 cmp.ltu p6,p0=result1[0],word1[0] // check the carry 188 cmp.eq.or.andcm p8,p0=0,count // exit if zero 8-byte 189 ;; 190(p6) adds result1[0]=1,result1[0] 191(p8) br.cond.dptk .do_csum_exit // if (within an 8-byte word) 192(p11) br.cond.dptk .do_csum16 // if (count is even) 193 194 // Here count is odd. 195 ld8 word1[1]=[first1],8 // load an 8-byte word 196 cmp.eq p9,p10=1,count // if (count == 1) 197 adds count=-1,count // loaded an 8-byte word 198 ;; 199 add result1[0]=result1[0],word1[1] 200 ;; 201 cmp.ltu p6,p0=result1[0],word1[1] 202 ;; 203(p6) adds result1[0]=1,result1[0] 204(p9) br.cond.sptk .do_csum_exit // if (count == 1) exit 205 // Fall through to calculate the checksum, feeding result1[0] as 206 // the initial value in result1[0]. 207 // 208 // Calculate the checksum loading two 8-byte words per loop. 209 // 210.do_csum16: 211 add first2=8,first1 212 shr.u count=count,1 // we do 16 bytes per loop 213 ;; 214 adds count=-1,count 215 mov carry1=r0 216 mov carry2=r0 217 brp.loop.imp 1f,2f 218 ;; 219 mov ar.ec=PIPE_DEPTH 220 mov ar.lc=count // set lc 221 mov pr.rot=1<<16 222 // result1[0] must be initialized in advance. 223 mov result2[0]=r0 224 ;; 225 .align 32 2261: 227(ELD_1) cmp.ltu pC1[0],p0=result1[LOAD_LATENCY],word1[LOAD_LATENCY+1] 228(pC1[1])adds carry1=1,carry1 229(ELD_1) cmp.ltu pC2[0],p0=result2[LOAD_LATENCY],word2[LOAD_LATENCY+1] 230(pC2[1])adds carry2=1,carry2 231(ELD) add result1[LOAD_LATENCY-1]=result1[LOAD_LATENCY],word1[LOAD_LATENCY] 232(ELD) add result2[LOAD_LATENCY-1]=result2[LOAD_LATENCY],word2[LOAD_LATENCY] 2332: 234(p[0]) ld8 word1[0]=[first1],16 235(p[0]) ld8 word2[0]=[first2],16 236 br.ctop.sptk 1b 237 ;; 238 // Since len is a 32-bit value, carry cannot be larger than a 64-bit value. 239(pC1[1])adds carry1=1,carry1 // since we miss the last one 240(pC2[1])adds carry2=1,carry2 241 ;; 242 add result1[LOAD_LATENCY+1]=result1[LOAD_LATENCY+1],carry1 243 add result2[LOAD_LATENCY+1]=result2[LOAD_LATENCY+1],carry2 244 ;; 245 cmp.ltu p6,p0=result1[LOAD_LATENCY+1],carry1 246 cmp.ltu p7,p0=result2[LOAD_LATENCY+1],carry2 247 ;; 248(p6) adds result1[LOAD_LATENCY+1]=1,result1[LOAD_LATENCY+1] 249(p7) adds result2[LOAD_LATENCY+1]=1,result2[LOAD_LATENCY+1] 250 ;; 251 add result1[0]=result1[LOAD_LATENCY+1],result2[LOAD_LATENCY+1] 252 ;; 253 cmp.ltu p6,p0=result1[0],result2[LOAD_LATENCY+1] 254 ;; 255(p6) adds result1[0]=1,result1[0] 256 ;; 257.do_csum_exit: 258 // 259 // now fold 64 into 16 bits taking care of carry 260 // that's not very good because it has lots of sequentiality 261 // 262 mov tmp3=0xffff 263 zxt4 tmp1=result1[0] 264 shr.u tmp2=result1[0],32 265 ;; 266 add result1[0]=tmp1,tmp2 267 ;; 268 and tmp1=result1[0],tmp3 269 shr.u tmp2=result1[0],16 270 ;; 271 add result1[0]=tmp1,tmp2 272 ;; 273 and tmp1=result1[0],tmp3 274 shr.u tmp2=result1[0],16 275 ;; 276 add result1[0]=tmp1,tmp2 277 ;; 278 and tmp1=result1[0],tmp3 279 shr.u tmp2=result1[0],16 280 ;; 281 add ret0=tmp1,tmp2 282 mov pr=saved_pr,0xffffffffffff0000 283 ;; 284 // if buf was odd then swap bytes 285 mov ar.pfs=saved_pfs // restore ar.ec 286(p15) mux1 ret0=ret0,@rev // reverse word 287 ;; 288 mov ar.lc=saved_lc 289(p15) shr.u ret0=ret0,64-16 // + shift back to position = swap bytes 290 br.ret.sptk.many rp 291 292// I (Jun Nakajima) wrote an equivalent code (see below), but it was 293// not much better than the original. So keep the original there so that 294// someone else can challenge. 295// 296// shr.u word1[0]=result1[0],32 297// zxt4 result1[0]=result1[0] 298// ;; 299// add result1[0]=result1[0],word1[0] 300// ;; 301// zxt2 result2[0]=result1[0] 302// extr.u word1[0]=result1[0],16,16 303// shr.u carry1=result1[0],32 304// ;; 305// add result2[0]=result2[0],word1[0] 306// ;; 307// add result2[0]=result2[0],carry1 308// ;; 309// extr.u ret0=result2[0],16,16 310// ;; 311// add ret0=ret0,result2[0] 312// ;; 313// zxt2 ret0=ret0 314// mov ar.pfs=saved_pfs // restore ar.ec 315// mov pr=saved_pr,0xffffffffffff0000 316// ;; 317// // if buf was odd then swap bytes 318// mov ar.lc=saved_lc 319//(p15) mux1 ret0=ret0,@rev // reverse word 320// ;; 321//(p15) shr.u ret0=ret0,64-16 // + shift back to position = swap bytes 322// br.ret.sptk.many rp 323 324END(do_csum)