tnum.c (5225B)
1// SPDX-License-Identifier: GPL-2.0-only 2/* tnum: tracked (or tristate) numbers 3 * 4 * A tnum tracks knowledge about the bits of a value. Each bit can be either 5 * known (0 or 1), or unknown (x). Arithmetic operations on tnums will 6 * propagate the unknown bits such that the tnum result represents all the 7 * possible results for possible values of the operands. 8 */ 9#include <linux/kernel.h> 10#include <linux/tnum.h> 11 12#define TNUM(_v, _m) (struct tnum){.value = _v, .mask = _m} 13/* A completely unknown value */ 14const struct tnum tnum_unknown = { .value = 0, .mask = -1 }; 15 16struct tnum tnum_const(u64 value) 17{ 18 return TNUM(value, 0); 19} 20 21struct tnum tnum_range(u64 min, u64 max) 22{ 23 u64 chi = min ^ max, delta; 24 u8 bits = fls64(chi); 25 26 /* special case, needed because 1ULL << 64 is undefined */ 27 if (bits > 63) 28 return tnum_unknown; 29 /* e.g. if chi = 4, bits = 3, delta = (1<<3) - 1 = 7. 30 * if chi = 0, bits = 0, delta = (1<<0) - 1 = 0, so we return 31 * constant min (since min == max). 32 */ 33 delta = (1ULL << bits) - 1; 34 return TNUM(min & ~delta, delta); 35} 36 37struct tnum tnum_lshift(struct tnum a, u8 shift) 38{ 39 return TNUM(a.value << shift, a.mask << shift); 40} 41 42struct tnum tnum_rshift(struct tnum a, u8 shift) 43{ 44 return TNUM(a.value >> shift, a.mask >> shift); 45} 46 47struct tnum tnum_arshift(struct tnum a, u8 min_shift, u8 insn_bitness) 48{ 49 /* if a.value is negative, arithmetic shifting by minimum shift 50 * will have larger negative offset compared to more shifting. 51 * If a.value is nonnegative, arithmetic shifting by minimum shift 52 * will have larger positive offset compare to more shifting. 53 */ 54 if (insn_bitness == 32) 55 return TNUM((u32)(((s32)a.value) >> min_shift), 56 (u32)(((s32)a.mask) >> min_shift)); 57 else 58 return TNUM((s64)a.value >> min_shift, 59 (s64)a.mask >> min_shift); 60} 61 62struct tnum tnum_add(struct tnum a, struct tnum b) 63{ 64 u64 sm, sv, sigma, chi, mu; 65 66 sm = a.mask + b.mask; 67 sv = a.value + b.value; 68 sigma = sm + sv; 69 chi = sigma ^ sv; 70 mu = chi | a.mask | b.mask; 71 return TNUM(sv & ~mu, mu); 72} 73 74struct tnum tnum_sub(struct tnum a, struct tnum b) 75{ 76 u64 dv, alpha, beta, chi, mu; 77 78 dv = a.value - b.value; 79 alpha = dv + a.mask; 80 beta = dv - b.mask; 81 chi = alpha ^ beta; 82 mu = chi | a.mask | b.mask; 83 return TNUM(dv & ~mu, mu); 84} 85 86struct tnum tnum_and(struct tnum a, struct tnum b) 87{ 88 u64 alpha, beta, v; 89 90 alpha = a.value | a.mask; 91 beta = b.value | b.mask; 92 v = a.value & b.value; 93 return TNUM(v, alpha & beta & ~v); 94} 95 96struct tnum tnum_or(struct tnum a, struct tnum b) 97{ 98 u64 v, mu; 99 100 v = a.value | b.value; 101 mu = a.mask | b.mask; 102 return TNUM(v, mu & ~v); 103} 104 105struct tnum tnum_xor(struct tnum a, struct tnum b) 106{ 107 u64 v, mu; 108 109 v = a.value ^ b.value; 110 mu = a.mask | b.mask; 111 return TNUM(v & ~mu, mu); 112} 113 114/* Generate partial products by multiplying each bit in the multiplier (tnum a) 115 * with the multiplicand (tnum b), and add the partial products after 116 * appropriately bit-shifting them. Instead of directly performing tnum addition 117 * on the generated partial products, equivalenty, decompose each partial 118 * product into two tnums, consisting of the value-sum (acc_v) and the 119 * mask-sum (acc_m) and then perform tnum addition on them. The following paper 120 * explains the algorithm in more detail: https://arxiv.org/abs/2105.05398. 121 */ 122struct tnum tnum_mul(struct tnum a, struct tnum b) 123{ 124 u64 acc_v = a.value * b.value; 125 struct tnum acc_m = TNUM(0, 0); 126 127 while (a.value || a.mask) { 128 /* LSB of tnum a is a certain 1 */ 129 if (a.value & 1) 130 acc_m = tnum_add(acc_m, TNUM(0, b.mask)); 131 /* LSB of tnum a is uncertain */ 132 else if (a.mask & 1) 133 acc_m = tnum_add(acc_m, TNUM(0, b.value | b.mask)); 134 /* Note: no case for LSB is certain 0 */ 135 a = tnum_rshift(a, 1); 136 b = tnum_lshift(b, 1); 137 } 138 return tnum_add(TNUM(acc_v, 0), acc_m); 139} 140 141/* Note that if a and b disagree - i.e. one has a 'known 1' where the other has 142 * a 'known 0' - this will return a 'known 1' for that bit. 143 */ 144struct tnum tnum_intersect(struct tnum a, struct tnum b) 145{ 146 u64 v, mu; 147 148 v = a.value | b.value; 149 mu = a.mask & b.mask; 150 return TNUM(v & ~mu, mu); 151} 152 153struct tnum tnum_cast(struct tnum a, u8 size) 154{ 155 a.value &= (1ULL << (size * 8)) - 1; 156 a.mask &= (1ULL << (size * 8)) - 1; 157 return a; 158} 159 160bool tnum_is_aligned(struct tnum a, u64 size) 161{ 162 if (!size) 163 return true; 164 return !((a.value | a.mask) & (size - 1)); 165} 166 167bool tnum_in(struct tnum a, struct tnum b) 168{ 169 if (b.mask & ~a.mask) 170 return false; 171 b.value &= ~a.mask; 172 return a.value == b.value; 173} 174 175int tnum_strn(char *str, size_t size, struct tnum a) 176{ 177 return snprintf(str, size, "(%#llx; %#llx)", a.value, a.mask); 178} 179EXPORT_SYMBOL_GPL(tnum_strn); 180 181int tnum_sbin(char *str, size_t size, struct tnum a) 182{ 183 size_t n; 184 185 for (n = 64; n; n--) { 186 if (n < size) { 187 if (a.mask & 1) 188 str[n - 1] = 'x'; 189 else if (a.value & 1) 190 str[n - 1] = '1'; 191 else 192 str[n - 1] = '0'; 193 } 194 a.mask >>= 1; 195 a.value >>= 1; 196 } 197 str[min(size - 1, (size_t)64)] = 0; 198 return 64; 199} 200 201struct tnum tnum_subreg(struct tnum a) 202{ 203 return tnum_cast(a, 4); 204} 205 206struct tnum tnum_clear_subreg(struct tnum a) 207{ 208 return tnum_lshift(tnum_rshift(a, 32), 32); 209} 210 211struct tnum tnum_const_subreg(struct tnum a, u32 value) 212{ 213 return tnum_or(tnum_clear_subreg(a), tnum_const(value)); 214}