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| author | Louis Burda <quent.burda@gmail.com> | 2023-04-07 17:18:18 -0400 |
|---|---|---|
| committer | Louis Burda <quent.burda@gmail.com> | 2023-04-07 17:19:39 -0400 |
| commit | 87ab487d59fa85dbe2afa55cc841b02805ae42ca (patch) | |
| tree | cd90ab715e1b5b5803674045dbafd6d51d27ac90 /src/19/part2 | |
| parent | 1bcc82c5bfbde87edd03c01ffdf9ee5934681592 (diff) | |
| download | aoc2018-python-87ab487d59fa85dbe2afa55cc841b02805ae42ca.tar.gz aoc2018-python-87ab487d59fa85dbe2afa55cc841b02805ae42ca.zip | |
Reorder days into src
Diffstat (limited to 'src/19/part2')
| -rw-r--r-- | src/19/part2 | 58 |
1 files changed, 58 insertions, 0 deletions
diff --git a/src/19/part2 b/src/19/part2 new file mode 100644 index 0000000..3bfe430 --- /dev/null +++ b/src/19/part2 @@ -0,0 +1,58 @@ +--- Part Two --- + +You aren't sure how large Santa's ship is. You aren't even sure if you'll need to use this thing on +Santa's ship, but it doesn't hurt to be prepared. You figure Santa's ship might fit in a +[1m[97m100x100[0m square. + +The beam gets wider as it travels away from the emitter; you'll need to be a minimum distance away +to fit a square of that size into the beam fully. (Don't rotate the square; it should be aligned to +the same axes as the drone grid.) + +For example, suppose you have the following tractor beam readings: + +#....................................... +.#...................................... +..##.................................... +...###.................................. +....###................................. +.....####............................... +......#####............................. +......######............................ +.......#######.......................... +........########........................ +.........#########...................... +..........#########..................... +...........##########................... +...........############................. +............############................ +.............#############.............. +..............##############............ +...............###############.......... +................###############......... +................#################....... +.................########[1m[97mO[0mOOOOOOOOO..... +..................#######OOOOOOOOOO#.... +...................######OOOOOOOOOO###.. +....................#####OOOOOOOOOO##### +.....................####OOOOOOOOOO##### +.....................####OOOOOOOOOO##### +......................###OOOOOOOOOO##### +.......................##OOOOOOOOOO##### +........................#OOOOOOOOOO##### +.........................OOOOOOOOOO##### +..........................############## +..........................############## +...........................############# +............................############ +.............................########### + +In this example, the [1m[97m10x10[0m square closest to the emitter that fits entirely within the tractor beam +has been marked O. Within it, the point closest to the emitter (the only highlighted [1m[97mO[0m) is at X=25, +Y=20. + +Find the [1m[97m100x100[0m square closest to the emitter that fits entirely within the tractor beam; within +that square, find the point closest to the emitter. [1m[97mWhat value do you get if you take that point's +X coordinate, multiply it by 10000, then add the point's Y coordinate?[0m (In the example above, this +would be 250020.) + + |